Hi Justin,
thanks for replying.
Yes the gain is 1000 volts per amp.
For example:
-120dBm to V/rt Hz than using the gain 1000V/A to get A/rt Hz
???_(???/??)=?_???−10 log(???) [-120-10log(10)]
?= (√(10^((?_???−30)/10)∗?))/???? (rt(10^((-130-30)/10)*50OHm)/1000V/A
I = 5E-10A/rt Hz
Is this the way to do?
BR
Flo